Python function to send a single Telegram message

This is my console.log equivalent when I need a quick observability implementation.

Usually, when you build a Telegram bot, you have to have a small server listening for updates.

The server logic is abstracted away as a simple API using the python-telegram-bot package, but we can write a simpler implementation for a single message:

import os
import telegram
TELEGRAM_BOT_ID = os.getenv("TELEGRAM_BOT_ID")
TELEGRAM_BOT_TOKEN = os.getenv("TELEGRAM_BOT_TOKEN")
async def send_telegra_notification(msg: str, origin: str = "AppName:main"):
    notification_msg = f"*{origin}*: {msg}"
    bot = telegram.Bot(token=TELEGRAM_BOT_TOKEN)
    try:
        await bot.initialize()
        await bot.send_message(
            chat_id=TELEGRAM_BOT_ID,
            text=notification_msg,
            parse_mode=telegram.constants.ParseMode.MARKDOWN,
        )
    except Exception as e:
        # handle exception, e.g., logger.error(e)
        print(e)
    finally:
        await bot.shutdown()